3x^2-60x+12=0

Solution for 3x^2-60x+12=0 equation:

3x^2-60x+12=0

a = 3; b = -60; c = +12;
Δ = b2-4ac
Δ = -602-4·3·12
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-24\sqrt{6}}{2*3}=\frac{60-24\sqrt{6}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+24\sqrt{6}}{2*3}=\frac{60+24\sqrt{6}}{6}
$